In which list are the ions ranked in order of increasing ionic radius?
17% of national qualifiers got this right
Explanation
draftIonic radius depends on both electron configuration (isoelectronic comparisons) and position in the group (period).
- and are isoelectronic (both have the core, 18 electrons). Since has more protons (20) pulling on the same electron shell than (19 protons), is smaller: .
- Similarly, and are isoelectronic (both have the core, 36 electrons). has more protons (38) than (37), so .
- Down a group, ionic radius increases due to added electron shells, so (Group 2) and (Group 1).
Putting these relationships together using actual measured radii ( pm, pm, pm, pm):
This matches choice (C).
Assumes ionic radius depends only on group position (same charge groups compared separately) and ignores that higher charge for the same electron configuration shrinks the ion; incorrectly ranks before the ions and swaps / position relative to .
Mixes up the isoelectronic pairing—compares to correctly (smaller charge = larger radius) but then incorrectly places before , forgetting that 's extra proton makes it smaller than , not larger.
Correctly uses isoelectronic comparisons (higher charge = smaller radius for same electron count) and group trends (radius increases down a group) to get .
Incorrectly interleaves the ions by treating and charges as if they alternate by period only, placing between and without properly comparing isoelectronic species; ignores that (Kr core) is smaller than ... actually reverses the correct relationship, showing confusion about which ions share electron configurations.
USNCO 2019 National Part I exam, question 44. © American Chemical Society; reproduced for non-commercial practice.